My application is such that if it throws an exception I want the driver to close, I tried the following code but it is throwing exception .
My code: where url is the url I want to open
driver=webdriver.Firefox()
try:
driver.get(url)
except:
driver.quit()
It is closing the driver but throwing an exception. How should I fix this?
This is my stacktrace
raceback (most recent call last):
File "/folderpath", line 47, in <module>
driver.close()
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 505, in close
self.execute(Command.CLOSE)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 231, in execute
response = self.command_executor.execute(driver_command, params)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/remote_connection.py", line 395, in execute
return self._request(command_info[0], url, body=data)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/remote_connection.py", line 425, in _request
self._conn.request(method, parsed_url.path, body, headers)
File "/usr/lib/python2.7/httplib.py", line 973, in request
self._send_request(method, url, body, headers)
File "/usr/lib/python2.7/httplib.py", line 1007, in _send_request
self.endheaders(body)
File "/usr/lib/python2.7/httplib.py", line 969, in endheaders
self._send_output(message_body)
File "/usr/lib/python2.7/httplib.py", line 829, in _send_output
self.send(msg)
File "/usr/lib/python2.7/httplib.py", line 791, in send
self.connect()
File "/usr/lib/python2.7/httplib.py", line 772, in connect
self.timeout, self.source_address)
File "/usr/lib/python2.7/socket.py", line 571, in create_connection
raise err
socket.error: [Errno 111] Connection refused