Why isn't PHP receiving an array of values?

Question

I am passing multiple values to PHP with the same name using ajax. But when I dump the array, only the last value is shown.

The serialized form:

genres=59&genres=13&genres=15&genres=14&genres=16&genres=17&genres=18&genres=19&genres=20&genres=21&genres=22&genres=23&genres=24&accepted-media=1&special-instructions=&g-recaptcha-response=&userid=62&action=search

**PHP*

"genres=" . var_dump(array($_REQUEST["genres"])) . "\n";

array (size=1)
0 => string '24' (length=2)

JavaScript

$("#form-enablers").on("submit", function () {
    $("#userid").val(localStorage.getItem("account-id"));
    var data = $("#form-enablers").serialize() + "&action=search";
    console.log(data);
    ajax('post', 'php/enablers.php', data, success, "Error searching: ");
    function success(table) {
        console.log(table);
        $('#table-list').empty().append(table);
        $("#writers-list").css({ "display": "block" });
    }
});

Needs to be `genres=59[]&genres=13[]&genres=15[]&genres[]=14&genres[]=16...` — Jonnix, Jun 05 '16 at 13:58

score 2 · Accepted Answer · answered Jun 05 '16 at 13:57

2

If you want to pass an array of values in a request, a special syntax is required. You need to add brackets [] to attribute name in order to put all attributes in an array.

In your case the serialized data should look like the following:

genres[]=59&genres[]=13&genres[]=15&genres[]=14&genres[]=16&genres[]=17&genres[]=18&genres[]=19&genres[]=20&genres[]=21&genres[]=22&genres[]=23&genres[]=24&accepted-media=1&special-instructions=&g-recaptcha-response=&userid=62&action=search

This way $_REQUEST['genres'] will contain an array of values instead of a single value.

answered Jun 05 '16 at 13:57

jedrzej.kurylo

39,591
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I changed the name to ( – ron tornambe Jun 05 '16 at 14:12
How are you serializing the data from the form? – jedrzej.kurylo Jun 05 '16 at 14:17
I amended the question to include the ajax call. – ron tornambe Jun 05 '16 at 14:29

score 0 · Answer 2 · edited May 23 '17 at 12:15

0

Click here, is similar to your question though is not in Ajax

The main point is the name of the values need to have square brackets [] .

edited May 23 '17 at 12:15

Community

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answered Jun 05 '16 at 13:58

Shing Kae

11
2

Why isn't PHP receiving an array of values?

2 Answers2