I'm parsing remote data in to my app and uses it through arguments. One of the data types is a url adresse i want to open in the url. I have an idea that I have to open it with the openURL function but I can't seem to get it to work. Anyone have a working example?
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Mike, please provide the relevant part of your nonworking code, and the errors you get (if any). See [how-to-ask](https://stackoverflow.com/help/how-to-ask) for details on how to ask a good question. – Patrick De Marta Jun 06 '16 at 07:47
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You have to utilize in-built HttpClient
var url = "http://www.you_remote_url.com";
var client = Ti.Network.createHTTPClient({
// function called when the response data is available
onload : function(e) {
Ti.API.info("Received text: " + this.responseText);
alert('success');
},
// function called when an error occurs, including a timeout
onerror : function(e) {
Ti.API.debug(e.error);
alert('error');
},
timeout : 5000 // in milliseconds
});
// Prepare the connection.
client.open("GET", url);
// Send the request.
client.send();

Zumry Mohamed
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