Define a protocol that will serve as a selection, wether the extensions should be available or not:
protocol UIViewExtensions { }
then define an extension for the protocol, but only for subclasses of UIView
(the other way around won't work):
extension UIViewExtensions where Self: UIView {
func testFunc() -> String { return String(tag) }
}
A class that is defined to have the protocol will also have the extension:
class A: UIView, UIViewExtensions { }
A().testFunc() //has the extension
And if it is not defined to have the protocol, it will also not have the extension:
class B: UIView {}
B().testFunc() //execution failed: MyPlayground.playground:17:1: error: value of type 'B' has no member 'testFunc'
UPDATE
Since protocol extensions don't do class polymorphism, if you need to override functions, the only thing I can think of is to subclass:
class UIViewWithExtensions: UIView {
override func canBecomeFocused() -> Bool { return true }
}
UIViewWithExtensions().canBecomeFocused() // returns true
this could also be combined with the extension, but I don't think it would still make much sense anymore.