Getting Number format exception

Question

I am getting number format exception, not sure what I am doing wrong.

public static void main(String[] args) {

    int v = 1476423;
    double d = v;
    System.out.println("Double "+v);
    String s = String.valueOf(d);
    System.out.println("String "+s);
    v = Integer.parseInt(s);
    System.out.println("Integer "+v);
}

When I am trying to print v, it is giving number format exception. Can somebody help here?

Error:

Double 1476423
String 1476423.0
Exception in thread "main" java.lang.NumberFormatException: For input string: "1476423.0"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:580)
    at java.lang.Integer.parseInt(Integer.java:615)
    at testCases.Random.main(Random.java:12)

You can't parse a floating point number to an Integer – OneCricketeer Jun 08 '16 at 02:34 — OneCricketeer, Jun 08 '16 at 02:34

score 2 · Answer 1 · answered Jun 08 '16 at 02:35

2

This is clearly not an integer value, it has a decimal part, even though it's zero:

"1476423.0"

Either do this:

int v = Integer.parseInt("1476423");

Or this:

double d = Double.parseDouble("1476423.0");

answered Jun 08 '16 at 02:35

Óscar López

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i was just trying other stuff, actually the problem is I am getting a `string` with a `.` so I wanted to convert it into `int` and remove the `.0` – DisplayName Jun 08 '16 at 06:01
Then remove it, see my answer here: http://stackoverflow.com/a/10372905/201359 – Óscar López Jun 08 '16 at 13:29
If the above answered your question, please don't forget to accept it, just click on the check mark to its left – Óscar López Jun 08 '16 at 14:10

score 0 · Answer 2 · answered Jun 08 '16 at 02:37

0

You can fix the problem by deleting this line

v = Integer.parseInt(s);

But the problem is that double d = v; makes v a floating point number, which you convert to a string, then try to convert back to an int, which is not very clear why you do that because you aren't changing the value of v in any way.

answered Jun 08 '16 at 02:37

OneCricketeer

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i was just trying other stuff, actually the problem is I am getting a `string` with a `.` so I wanted to convert it into `int` and remove the `.0` – DisplayName Jun 08 '16 at 06:01
Yes, a string representation of a floating point number (in other words, a decimal) cannot be parsed to an int because integers do not contain decimals – OneCricketeer Jun 08 '16 at 06:02

Getting Number format exception

2 Answers2