I want to edit the last part of the date from "20" to "2015" Which function should I use?

Question

 [1] "18-12-20" "18-12-20" "04-12-20" "27-11-20" "12-11-20" "30-10-20" "30-10-20"
 [8] "30-10-20" "22-10-20" "16-10-20" "09-10-20" "02-10-20" "02-10-20" "25-09-20"
[15] "25-09-20" "18-09-20" "11-09-20" "04-09-20" "28-08-20" "21-08-20" "21-08-20"
[22] "14-08-20" "07-08-20" "31-07-20" "17-07-20" "03-07-20" "26-06-20" "19-06-20"
[29] "12-06-20" "05-06-20" "28-05-20" "22-05-20" "15-05-20" "08-05-20" "08-05-20"
[36] "01-05-20" "17-04-20" "10-04-20" "20-03-20" "13-03-20" "06-03-20" "27-02-20"
[43] "27-02-20" "20-02-20" "13-02-20" "06-02-20" "30-01-20" "30-01-20" "23-01-20"
[50] "23-01-20" "16-01-20" "09-01-20"

How to replace the last part of the string with a new string ? I want to replace the last part "20" with "2015"

Possible duplicate of [How to format a JavaScript date](http://stackoverflow.com/questions/3552461/how-to-format-a-javascript-date) — Halfpint, Jun 09 '16 at 13:46
use the `gsub()` function: `gsub("*20$", replacement = "2015", x = "your_string_name" )` — J_F, Jun 09 '16 at 13:46
@DeepakBhattacharya you can accept any answer if it works for you. — Ronak Shah, Jun 09 '16 at 17:14

score 1 · Answer 1 · answered Jun 09 '16 at 13:50

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gsub will work fine for this

gsub("-20", "-2015", df)

answered Jun 09 '16 at 13:50

rar

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Ronak Shah · Answer 2 · 2016-06-09T14:11:09.390

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You could use sub.

*20 means it can accommodate anything before 20 whereas $ in the end ensures that it is the end of vector and nothing is present after that. Hence, this helps in case if there is date with value 20.

sub("*20$", "2015", x)

where x is the vector you want to replace.

edited Jun 09 '16 at 14:11

answered Jun 09 '16 at 13:48

Ronak Shah

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This wont replace any date with 20 ? i just want to edit the year from 20 to 2015 – Deepak Bhattacharya Jun 09 '16 at 13:56
Can you please explain the use of various symbols like *,$,^ while using sub.Thanks – Deepak Bhattacharya Jun 09 '16 at 14:03
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Thanks :) That was really helpful :) – Deepak Bhattacharya Jun 09 '16 at 14:25

score 0 · Answer 3 · answered Jun 09 '16 at 14:04

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Another method is to paste "15" to the end of each element:

temp <- c("18-12-20", "18-12-20", "04-12-20")
paste(temp, "15", sep="")
[1] "18-12-2015" "18-12-2015" "04-12-2015"

or

paste0(temp, "15")

answered Jun 09 '16 at 14:04

lmo

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I want to edit the last part of the date from "20" to "2015" Which function should I use?

3 Answers3