Why following function cant be called with given argument list?

Question

 void conver(double&, int&);
 private: System::Void cb1_SelectedIndexChanged(System::Object^  sender, System::EventArgs^  e) {

         a=1;
         if ((a==1)&&(b2==1))
         {if(cb1->Text=="Celsius")
             {
                 input=System::Convert::ToDouble(cel->Text);
                 if (cb2->Text=="Celsius")
                 {
                     choice=1;
                     conver(input,choice);
                 } 
                 if(cb2->Text=="Fahrenheit")    
             }   
         }
     }

I am getting the following error:

Error: function "Project3::MyForm::conver" cannot be called with the given argument list. argument types are: (double, int)

I don't understand what this means. Can't we pass arguments by reference in Visual C++?

Where is `input` even defined? This code is incomplete, and therefore the question does not make any sense. — Cody Gray - on strike, Jun 11 '16 at 10:27

score 0 · Accepted Answer · answered Jun 11 '16 at 05:47

0

You are passing an actual number - not a variable - by reference. You cannot pass in numbers by reference because numbers do not have addresses assigned in the registry (memory). You will have to use a variable.

You can do for example:

int myFirstNumber = 1;
int mySecondNumber = 1;

conver(myFirstNumber, mySecondNumber);

answered Jun 11 '16 at 05:47

Jossie Calderon

1,393
12
21

@Amar30657: Have you tried this solution? How did it work for you? – Jossie Calderon Jun 11 '16 at 05:55
i wasnt seeking lik that itll probably work i guess but can u review my code again – Jun 11 '16 at 05:57
1

@Amar30657, please create a new question for a different issue in the future. This drives the answerer to give much effort with no visible result. If the first answer helped you, please click the up-arrow to this answer. – Jossie Calderon Jun 11 '16 at 05:58
u help i click if it was that so then why did stack ovrflow give edit option man come on help – Jun 11 '16 at 06:00
1

@Amar30657: editing is for revising and **improving** posts. – Jossie Calderon Jun 11 '16 at 06:02

score 0 · Answer 2 · answered Jun 11 '16 at 05:48

0

If I am not wrong

conver(int&, int&);

needs integer reference variable

conver(1,1);

and you are passing constants

Try passing int variables

answered Jun 11 '16 at 05:48

Priyesh Kumar

2,837
1
15
29

score 0 · Answer 3 · answered Jun 11 '16 at 05:49

0

conver(1,1);

You're passing numbers instead of variables.

answered Jun 11 '16 at 05:49

merelyMark

367
3
9

Shouldn't it be: void conver(double%, int%); for CLI/C++? – merelyMark Jun 11 '16 at 06:00

Why following function cant be called with given argument list?

3 Answers3