Find values from JSON string on the basis of dropdown selection values

Asked Jun 12 '16 at 07:44

Active Jun 12 '16 at 17:06

Viewed 26 times

I have a JSON string in a session. If I pass the index 1000 in the array then I get a value, but when passing a dynamic value coming from the previous page then I get the error:

Undefined index: [6000 ] in D:\xampp\htdocs\vendor\ajaxItemSelect.php on line 23

My code:

<?php
    session_start();
    $jsonString = isset($_SESSION['jsonString']) ? $_SESSION['jsonString'] : '';
    if (isset($_REQUEST['selectedvalues'])){
        $selectedvalues = isset($_POST['selectedvalues']) ? $_POST['selectedvalues'] : '';
?>

<div class="form-group"><label class="control-label">

    <?php echo $jsonString['m_materialSupportedList'][1000]['itemName']['en'];

    echo $jsonString['m_materialSupportedList'][$selectedval]['itemFieldOneLabel']['en']; ?>
</label>
<?php } ?>

edited Jun 12 '16 at 17:06

Peter Mortensen

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asked Jun 12 '16 at 07:44

Narayan Singh

2

Duplicate? http://stackoverflow.com/questions/4261133/php-notice-undefined-variable-and-notice-undefined-index – M. Eriksson Jun 12 '16 at 07:48
Check the index exists before you access it. – Stacked Jun 12 '16 at 10:58
Where in your code does `$selectedval` get set? Is that supposed to be `$selectedvalues`?? – bloodyKnuckles Jun 12 '16 at 13:05

Find values from JSON string on the basis of dropdown selection values

0 Answers0