Why list1 is valid way of instantiation but not list2?
List<List<T>> list1 = new ArrayList<List<T>>();
List<List<T>> list2 = new ArrayList<ArrayList<T>>();
I want to create a list of type list i.e.
new ArrayList<ArrayList<T>>();
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Mohammed
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Also exact duplicate of http://stackoverflow.com/questions/20702635/why-does-this-not-compile-listliststring-lss-new-arraylistarrayliststr – Tunaki Jun 12 '16 at 16:51
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1Google diamond operator, it will make the initialization simple. – Mick Mnemonic Jun 12 '16 at 16:51