create a list with a variable part

Question

I would like to create a list with a variable part :

mylist = ['a1','a2','a3','a4','a5']

I am trying :

i = range(1,5)
ii = [str(x) for x in i]

which works, and then I would like to do :

mylist = list('a' + x for x in ii)

but that doesn't work

The part you think is working is actually wrong, and the part you think doesn't work looks fine to me. — user2357112, Jun 13 '16 at 17:14
I am very sorry for the typo in the "range function". I'll be more focused next time. I get a - 'list' object is not callable - error... — salim, Jun 13 '16 at 17:20
When you post to SO, don't type in your code, copy paste it. — Alex Hall, Jun 13 '16 at 17:26

score 0 · Accepted Answer · edited May 23 '17 at 12:15

Ranges are half-open in Python so you must use xrange(1,6), and although concatenation is fine (between two strings) you could also use str.format. You can iterate over the numbers and append them to a in one go in a list comprehension with xrange ( see xrange vs range) such that you don't need to create two temporary lists in the process as you did:

>>> [str.format('a{0}', x) for x in xrange(1,6)]
['a1', 'a2', 'a3', 'a4', 'a5']
>>> ['a' + str(x) for x in xrange(1,6)]
['a1', 'a2', 'a3', 'a4', 'a5']

create a list with a variable part

1 Answers1