Why would you wrap a function expression in parenthesis in javascript (Not IIFE)?

Question

I was trying to acquaint myself with some advanced javascript and have been reading some of the jquery code on github when, I came across a anonymous function wrapped in parenthesis here.

Now, I am already aware of the concept of IIFE and the plethora of questions on SO regarding the subject, for instance - IIFE question here. But, this is not an IIFE, at least, is not invoked immediately IMHO.

I'm trying to figure out the use of such code and how it fits into the larger scheme of things. Since, the function is anonymous, I'm wondering how it is called or referenced.

Not quite sure what you're talking about, but the linked Git clearly has a regular, standard, wrapping IIFE ? — adeneo, Jun 15 '16 at 18:37
Is the function immediately invoked? Here is a fiddle https://jsfiddle.net/zxw2jtx3/ to explain what I mean. — Neil DCruz, Jun 15 '16 at 18:41
The top function of your fiddle is not invoked. What is your question though? — mariocatch, Jun 15 '16 at 18:44
It was an oversight, looks like my question has already been answered. — Neil DCruz, Jun 15 '16 at 18:45
I'm not even sure anyone here knows what your question is still. But glad you found what you were looking for. — mariocatch, Jun 15 '16 at 18:45

score 2 · Accepted Answer · answered Jun 15 '16 at 18:39

2

It is an IIFE -- it just gets called with a very long argument.

( function( global, factory ) {

    "use strict";

    // .....

// Pass this if window is not defined yet
} )( typeof window !== "undefined" ? window : this, function( window, noGlobal ) {
     // ...
    return jQuery;
} );

A function is passed as an argument, which gets used in the upper function. But it clearly is a standard IIFE otherwise.

answered Jun 15 '16 at 18:39

Scimonster

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Thanks, I feel silly for the oversight! – Neil DCruz Jun 15 '16 at 18:48

Why would you wrap a function expression in parenthesis in javascript (Not IIFE)?

1 Answers1