.bashrc giving error after settin $JAVA_HOME PATH

Question

I am getting the following error after setting JAVA_HOME path in bashrc:

bash: export: `=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/usr/local/games:/usr/lib/java/jdk1.8.0_91/bin': not a valid identifier

bashrc file:

#JAVA HOME directory setup
export JAVA_HOME="/usr/lib/java/jdk1.8.0_91"
export PATH =$PATH:$JAVA_HOME/bin

When I do echo_$JAVA_HOME, I get the correct path as: /usr/lib/java/jdk1.8.0_91

When I execute the command which java, I get the result as: /usr/bin/java

What can be the possible solution to solve this problem?

Use `update-java-alternatives` to set the correct JRE/JDK, and remove your bashrc changes. — Elliott Frisch, Jun 18 '16 at 04:02

score 5 · Accepted Answer · answered Jun 18 '16 at 04:03

5

In shell while setting a variable there should be no space between the valirable name and = character. Just change

export PATH =$PATH:$JAVA_HOME/bin

to

export PATH=$PATH:$JAVA_HOME/bin

answered Jun 18 '16 at 04:03

shanmuga

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Thanks, that worked. – Neel Shah Jun 18 '16 at 04:18

score 0 · Answer 2 · answered Jun 18 '16 at 04:08

0

Make JAVA_HOME at the front of your path. Otherwise /usr/bin/java will come before /usr/lib/java in the path search. And lose that leading space as shanmuga points out.

PATH=$JAVA_HOME/bin:$PATH

answered Jun 18 '16 at 04:08

selbie

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.bashrc giving error after settin $JAVA_HOME PATH

2 Answers2