int data[2][2] = {1,2,3,4};
int (*p)[2];
p = &data[0];
printf("%d\n",p);
printf("%d\n",data[0]);
printf("%d\n",&data[0]);
In this program the value of data[0] and &data[0] returns the same answer. Can anyone provide the explanation?
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Shashank Gupta
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1your tags answer the question itself. "reference", "pointer", "memory-address" – Akshansh Thakur Jun 18 '16 at 11:57
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You already equated the first and third with `p = &data[0];` – Weather Vane Jun 18 '16 at 12:03