I have a array (list) with times and now I need to determine if the eclipsed time is between two successive times from this list.
duurSeq=[11,16,22,29]
nu = time.time()
verstreken_tijd = nu - starttijd
for t in duurSeq:
if (verstreken_tijd > t ) and (verstreken_tijd < **t_next** ):
doSomething():
my question is: How do I get t_next (the next item in the array within the for loop)
Try this,
duurSeq=[11,16,22,29]
for c, n in zip(duurSeq, duurSeq[1:]):
if (verstreken_tijd > c) and (verstreken_tijd < n):
doSomething():
Refer to Iterate a list as pair (current, next) in Python for a general approach.
from itertools import tee, izip
def pairwise(iterable):
"s -> (s0,s1), (s1,s2), (s2, s3), ..."
a, b = tee(iterable)
next(b, None)
return izip(a, b)
# Demo
l = [11, 16, 22, 29]
for c, n in pairwise(l):
print(c, n)
# Output
(11, 16)
(16, 22)
(22, 29)
Sounds like you need some pointer arithmetic. See here for a great example.
TL/DR you can move to the next item in the array by telling the interpreter to move 1 block up the sizeof(int). Basically take the next integer in memory. This works only because you know the size of the elements in the array.
Use a foor loop on index instead of element
duurSeq = [11,16,22,29]
nu = time.time()
verstreken_tijd = nu - starttijd
for t in range(len(duurSeq)-1):
if verstreken_tijd > duurSeq[i] and verstreken_tijd < duurSeq[i+1]:
doSomething():
Looks like you want to access index of array inside for loop.
for index, element in enumerate(duurSeq):
# Use duurSeq[index] to access element at any position
