Most efficient way to check if an image is an image PHP

Question

I have a code which prints logos. The code checks if a file is an image or not.

Currently I'm using this code.

if(@is_array(getimagesize($mediapath))){
    $image = true;
} else {
    $image = false;
}

But my probems is that this is not very efficient. Maybe It's because it's logos from a external url, or maybe there is a more efficient way.

Any thoughts?

Possible duplicate of [PHP check if file is an image](http://stackoverflow.com/questions/15408125/php-check-if-file-is-an-image) — pes502, Jun 20 '16 at 07:46

score 0 · Answer 1 · answered Jun 20 '16 at 07:47

0

Use Below Function for check image.

int exif_imagetype ( string $filename )

URL: http://php.net/manual/en/function.exif-imagetype.php

answered Jun 20 '16 at 07:47

Virag Shah

64
2

this might be slitghtly more efficient but not perfect. – Edvard Åkerberg Jun 20 '16 at 08:08

score 0 · Answer 2 · answered Jun 20 '16 at 07:58

Try this.

$info = getimagesize($_FILES['ImageFile']['tmp_name']);
if ($info === FALSE) {
   die("Unable to determine image type of uploaded file");  
}
if (($info[2] !== IMAGETYPE_GIF) && ($info[2] !== IMAGETYPE_JPEG) && ($info[2] !== IMAGETYPE_PNG)) {
    die("Not a gif/jpeg/png");
}

Most efficient way to check if an image is an image PHP

2 Answers2