QFontMetrics boundingRect

Question

I'm having problems with the QFontMetrics 'boundingRect' function, it doesn't return the correct results.

    mfntArial = QFont("Arial", 12, QFont::Bold);
    QFontMetrics objMetrics(mfntArial);
    QRect rctLine = objMetrics.boundingRect("LOS");

In the debugger, rctLine contains:

This is very confusing, I would expect x1 and y1 to both be 0 since there is no reference position passed and I would expect both x2 and y2 to be positive.

The rectangle returned is not correct and if I use it with drawText and alignment then part of the string is missing from the display.

I know there are other posts regarding how this function returns the wrong results and I've looked at these, they didn't help me.

I am using Qt5.6 on RedHat 7.2.

I've also tried:

    QRect rctParent = pobjParent->geometry();
    QRect rctLine = objMetrics.boundingRect(rctParent, intAlign, "LOS");

Where pobjParent is the parent widget and rctParent contains:

intAlign contains 33 (left, top)

In this case rctLine returns:

But the bounding rextangle is still to small and part of the 'S' is missing when rendered.

Official Qt documentation on QFontMetrics

Same problem [here](http://stackoverflow.com/questions/27336001/qfontmetrics-returns-inaccurate-results). Documentation [here](http://doc.qt.io/qt-4.8/qfontmetrics.html#boundingRect-2). — LogicStuff, Jun 20 '16 at 13:10

score 0 · Accepted Answer · answered Jun 20 '16 at 13:20

I have fixed my problem by calculating the width of what I think is one of the widest characters, 'M'.

    QRect rctCapM = objMetrics.boundingRect(rctParent, intAlign, "M");

I then use this as a typical and then calculate the required bounding rectangle for other strings:

    QRect rctBounds(0, 0, rctCapM.width() * strLine.length(), rctCapM.height());

Where 'strLine' contains the string to display and calculate the bounds for, this works for me.

QFontMetrics boundingRect

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