You're misunderstanding the output of nm
. Scroll through man nm
and you'll you
read that the t
flag means the symbol is a local (static) symbol in
the text
section. The linker can't see it. If it were global (external)
the flag would be T
. So all four of your functions are local.
Contrast:
$ clang -shared -fPIC -fvisibility=hidden -o libdefaultvisibility.so defaultvisibility.c
$ nm libdefaultvisibility.so | grep ' t '
0000000000000570 t deregister_tm_clones
0000000000000600 t __do_global_dtors_aux
0000000000200e08 t __do_global_dtors_aux_fini_array_entry
0000000000000640 t frame_dummy
0000000000200e00 t __frame_dummy_init_array_entry
0000000000000670 t mylocalfunction1
0000000000000690 t mylocalfunction2
00000000000006b0 t mylocalfunction3
00000000000006d0 t printMessage
00000000000005b0 t register_tm_clones
with dropping the -fvisibility=hidden
:
$ clang -shared -fPIC -o libdefaultvisibility.so defaultvisibility.c
$ nm libdefaultvisibility.so | grep ' t '
0000000000000600 t deregister_tm_clones
0000000000000690 t __do_global_dtors_aux
0000000000200e08 t __do_global_dtors_aux_fini_array_entry
00000000000006d0 t frame_dummy
0000000000200e00 t __frame_dummy_init_array_entry
0000000000000700 t mylocalfunction1
0000000000000640 t register_tm_clones
$ nm libdefaultvisibility.so | grep ' T '
0000000000000780 T _fini
00000000000005b0 T _init
0000000000000720 T mylocalfunction2
0000000000000740 T mylocalfunction3
0000000000000760 T printMessage
Then only the explicitly hidden mylocalfunction1
remains local, and the
other three are now global.
You should not expect that a symbol marked with __attribute__ ((visibility("hidden")))
will be exported by a shared library in any circumstances. The attribute means precisely
that it will not be, whether it is applied explicitly to a symbol, as in this case,
or acquired by default in the presence of the linker option -fvisibility=hidden
.
If you want to export just that one function in the example by means of a visibility
attribution
you would have:
#define FOR_EXPORT __attribute__ ((visibility("default")))
Then:
$ clang -shared -fPIC -fvisibility=hidden -o libdefaultvisibility.so defaultvisibility.c
$ nm libdefaultvisibility.so | grep ' T '
0000000000000720 T _fini
0000000000000550 T _init
00000000000006a0 T mylocalfunction1
It is global, because the explicit attribition overrides the commandline option,
and all your other functions are local. Perhaps confusingly, default
visibility
is always public.
And you could accomplish this without resorting to visibility
attributions - which are
not portable - simply declaring all the functions that you don't want to export as static
. Then the compiler
would not expose them to the linker in the first place:
foo.c
#include <stdio.h>
void mylocalfunction1(void)
{
printf("function1\n");
}
static void mylocalfunction2(void)
{
printf("function2\n");
}
static void mylocalfunction3(void)
{
printf("function3\n");
}
static void printMessage(void)
{
printf("Running the function exported from the shared library\n");
}
With which you get again:-
$ clang -shared -fPIC -o libfoo.so foo.c
$ nm libfoo.so | grep ' T '
00000000000006c0 T _fini
0000000000000550 T _init
00000000000006a0 T mylocalfunction1
Although the distinction does not make itself felt in your example you
should understand that while a local/static symbol is not seen by the linker and (therefore) is unavailable for dynamic linkage, a global/external symbol
may or may not be available for dynamic linkage. visibility
controls the availability of global symbols for dynamic linkage, only.