php fatal error- Catchable fatal error: Object of class

Question

I am getting fatal error-

Catchable fatal error: Object of class TV could not be converted to string in /opt/lampp/htdocs/projects/oop/index.php on line 31.

What is is wrong here?

<?php

/**
* 
*/
class TV {

    public $model= 'xyz';
    public $volume= 1;

    function volumeUp()
    {
        $this->volume++;
    }

    function volumeDown() 
    {
        $this->volume--;
    }
}
//here we create new objects
$tv_one = new TV;
$tv_two = new TV;
//
$tv_one->volumeUp();

echo $tv_one->volume;

$tv_one->model;
//error on the following line
echo $tv_one;

`$tv_one` is an object. You can't just echo it. If you want to get the volume, use `$tv_one->volume` — Jonathan Kuhn, Jun 22 '16 at 18:07
`echo $tv_one` is bombing. In order to be able to `echo`, your class (TV) must provide a __toString() method e.g. convert to string. — YvesLeBorg, Jun 22 '16 at 18:10
And of course you can echo an object, implement the magical method [__toString](http://php.net/manual/de/language.oop5.magic.php#object.tostring) and you're good to go .. — dbf, Jun 23 '16 at 08:50

score 0 · Accepted Answer · answered Jun 22 '16 at 18:08

0

This is a valid statement to print a value to the page:

echo $tv_one->volume;

This isn't doing anything:

$tv_one->model;

It resolves to a value, but you don't do anything with that value. So that line of code is entirely useless and can just be removed.

This doesn't make sense:

echo $tv_one;

What do you expect the object to look like on the page? You echo values, not entire structures. So, exactly as you already do above, echo the value you want:

echo $tv_one->model;

answered Jun 22 '16 at 18:08

David

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echo $tv_one->volume; should say 1 – vaso123 Jun 22 '16 at 18:10
@lolka_bolka: I'm not sure what you mean, can you clarify? – David Jun 22 '16 at 18:13

php fatal error- Catchable fatal error: Object of class

1 Answers1