How to sum BigDecimal properties in java

Question

Let's get a simple example:

 Class Foo{
     private BigDecimal item1;
     private BigDecimal item2;
     private BigDecimal item3;
     private BigDecimal item4;
     private BigDecimal item5;
//setters and getters
   public BigDecimal getTotal(){
       BigDecimal total = BigDecimal.ZERO;
        if(null != item1){
            total =total .add(item1);
           }
        if(null != item2){
            total =total .add(item2);
           }
          ...
          ...
}
    }

I am summing in entity level. this is correct way or not?

can any one give me better code for getting total Value

put all the BigInteger in a list, and then loop for adding them all — VLEFF, Jun 23 '16 at 10:44
looking for this one? http://stackoverflow.com/a/1846918/592817 — tsohr, Jun 23 '16 at 10:45
You could use the streams API? Pass them in as a list, filter for null and then reduce — saml, Jun 23 '16 at 10:45
Make sure their values are not null by intializing them as zero first? — matt, Jun 23 '16 at 10:47

score 2 · Answer 1 · answered Jun 23 '16 at 10:51

Use a List<BigDecimal>

public BigDecimal getTotal(){
    List<BigDecimal> values =  Arrays.asList(item1, item2, item3, item4, item5)

    BigDecimal total = BigDecimal.ZERO;
    for (BigDecimal value : values) {
        if(value != null) {
            total = total.add(value);
        }
    }
    return total;
}

score 2 · Answer 2 · edited Jun 27 '16 at 14:57

2

You can use a loop to make your code simple :

import java.util.Arrays;

...

public BigDecimal getTotal(){
   BigDecimal total = BigDecimal.ZERO; 
   for(BigDecimal bd: Arrays.asList(item1,item2,item3,item4,item5)){
        if(null != bd){
            total =total .add(bd);
           }
    }
}

edited Jun 27 '16 at 14:57

phani

507
2
6
18

answered Jun 23 '16 at 10:53

Mifmif

3,132
18
23

score 0 · Answer 3 · answered Jun 23 '16 at 10:46

If you have a fixed (and little) amount of numbers you can do as follows:

            total = total.add(item1 ==null ? BigDecimal.ZERO : item1).add(item2 ==null ? BigDecimal.ZERO : item2).add(item3 ==null ? BigDecimal.ZERO : item3);

Adding 0 if the item is null and the item itself otherwise. IF you have a variable amount of items, then you need to iterate over them in a array or something like this:

for (BigDecimal current : myBigDecimalArray){
   total = total.add(current ==null ? BigDecimal.ZERO : current );
}

score 0 · Answer 4 · answered Nov 23 '21 at 16:21

If you don't mind using reflection:

public static BigDecimal sum(Object instance, String... fields) {
    BigDecimal total = BigDecimal.ZERO;
    for (String field : fields) {
        BigDecimal value = getProperty(instance, field);
        if (value != null) {
            total = total.add(value);
        }
    }
    return total;
}

Sample:

    annex.setOrTot(ReflectionUtils.sum(annex, "orEstadoOrg", "orSs", "orCcaa", "orCorpLoc", "orResto"));
    annex.setIdpTot(ReflectionUtils.sum(annex, "idpEstadoOrg", "idpSs", "idpCcaa", "idpCorpLoc", "idpResto"));
    annex.setDrTot(ReflectionUtils.sum(annex, "drEstadoOrg", "drSs", "drCcaa", "drCorPloc", "drResto"));
    annex.setIdcTot(ReflectionUtils.sum(annex, "idcEstadoOrg", "idcSS", "idcCcaa", "idcCorPloc", "idCresto"));

score 0 · Answer 5 · answered Jan 07 '23 at 07:25

0

java 8+, could use stream api

BigDecimal total = itemList.stream().reduce(BigDecimal.ZERO, BigDecimal::add);

answered Jan 07 '23 at 07:25

suxiaolin

11
3

How to sum BigDecimal properties in java

5 Answers5