How to get the Json format in android

Question

The json array format is

[{"restaurants": {
    "items1": [{
        "id": 4,
        "item_name": "Special Pizza",
        "image": ""
    }, {
        "id": 5,
        "item_name": "Veg Cheese Pizza",
        "image": ""
    }]
    "items2": [{
        "id": 4,
        "item_name": "Special Pizza",
        "image": ""
    }, {
        "id": 5,
        "item_name": "Veg Cheese Pizza",
        "image": ""
    }]
}}

I want to get the item1 & item2 to pass the value as a parent in Expandable ListView and pass the item_name into child. What to do to get the parent name and set into the setter method?

class AsyncT1 extends AsyncTask<String, Void, String> {
    @Override
    protected String doInBackground(String... params) {

        // http://abservetech.com/demoprojects/android/food_app/public/mobile/restaurant/restaurantresults


        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://abservetechdemo.com/projects/android/food_app/public/mobile/restaurant/resdetails");

        try {

            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
            nameValuePairs.add(new BasicNameValuePair("res_id","1"));
            nameValuePairs.add(new BasicNameValuePair("status","veg"));
            nameValuePairs.add(new BasicNameValuePair("main_cat","pizza"));

            // nameValuePairs.add(new BasicNameValuePair("group_id", group_id));
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            Log.e("mainToPost", "mainToPost" + nameValuePairs.toString());


     /* execute */

            // Execute HTTP Post Request
            HttpResponse response = httpclient.execute(httppost);
            InputStream inputStream = response.getEntity().getContent();
            InputStreamToStringExample str = new InputStreamToStringExample();
            String responseServer = str.getStringFromInputStream(inputStream);
            Log.d("response", "response -----" + responseServer);

            JSONObject jsonRootObject = new JSONObject(responseServer);
            JSONArray jsonArray = jsonRootObject.optJSONArray("restaurants");

            for (int i1 = 0; i1 < jsonArray.length(); i1++) {
                try {

                    ArrayList<Group> list = new ArrayList<Group>();
                    ArrayList<Child> ch_list= new ArrayList<Child>();

                    JSONObject jsonObject = jsonArray.getJSONObject(i1);
                    Group gru = new Group();


                    JSONArray ja = jsonObject.getJSONArray("item");
                    Log.d("subcategory---",s_category);
                    gru.setName(jsonObject.getJSONArray("items").toString());
                    for (int i = 0; i < ja.length(); i++) {

                        JSONObject jo = ja.getJSONObject(i);

                        Child ch = new Child();

                        ch.setName(jo.getString("item_name").toString());


                        ch_list.add(ch);
                    } // for loop end
                    gru.setItems(ch_list);
                    list.add(gru);
                    ExpAdapter = new ExpandListAdapter(
                            Expand.this, list);
                   runOnUiThread(new Runnable() {
                        @Override
                        public void run() {
                    ExpandList.setAdapter(ExpAdapter);}});

                }
                catch (JSONException e) {

                    e.printStackTrace();
                }


            }
        } catch (Exception e) {
            e.printStackTrace();
        }
        return null;
    }

    @Override
    protected void onPostExecute(String aVoid) {
        super.onPostExecute(aVoid);


    }
}

Logcat error:

     W/System.err: java.lang.NullPointerException
06-30 12:30:39.260 26691-26744/abservetech.com.foodapp W/System.err:     at abservetech.com.foodapp.Expand$AsyncT1.doInBackground(Expand.java:84)
06-30 12:30:39.260 26691-26744/abservetech.com.foodapp W/System.err:     at abservetech.com.foodapp.Expand$AsyncT1.doInBackground(Expand.java:50)
06-30 12:30:39.260 26691-26744/abservetech.com.foodapp W/System.err:     at android.os.AsyncTask$2.call(AsyncTask.java:288)
06-30 12:30:39.260 26691-26744/abservetech.com.foodapp W/System.err:     at java.util.concurrent.FutureTask.run(FutureTask.java:237)
06-30 12:30:39.260 26691-26744/abservetech.com.foodapp W/System.err:     at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:231)
06-30 12:30:39.260 26691-26744/abservetech.com.foodapp W/System.err:     at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)
06-30 12:30:39.260 26691-26744/abservetech.com.foodapp W/System.err:     at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)
06-30 12:30:39.260 26691-26744/abservetech.com.foodapp W/System.err:     at java.lang.Thread.run(Thread.java:841)

restaurants is a json object not json array – Vivek Mishra Jun 30 '16 at 07:06 — Vivek Mishra, Jun 30 '16 at 07:06
can u explain me clearly how to get the group name – ss ss Jun 30 '16 at 07:07 — ss ss, Jun 30 '16 at 07:07

score 0 · Answer 1 · answered Jun 30 '16 at 07:13

0

First thing restaurants is a json object not json array. To get your groups do it like this

JSONObject jsonRootObject = new JSONObject(responseServer);
JSONObject jsonobject=jsonRootObject.getJSONObject("restaurants");
JSONArray item1=jsonobject.getJSONArray("items1");
JSONArray item2=jsonobject.getJSONArray("items2");
for(int i=0;i<item1.length();i++)
{
JSONObject json=item1.getJSONArray(i);
String item_name=json.getString("item_name");
}

answered Jun 30 '16 at 07:13

Vivek Mishra

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ok thanks for ur post @vivek but i want to save the the item1&item2 into setter method.And also i dont know how may json array return from the the json.The json array value came at the run time.what to do for that? – ss ss Jun 30 '16 at 07:16
In that case you have to get your response format changed from backend . It should be wrapped inside a json array instead of json object. – Vivek Mishra Jun 30 '16 at 07:30
please explain that clearly,i want to wrap the JSONObject("restaurants") as JSONArray? – ss ss Jun 30 '16 at 07:35
no,your restaurants should be json array instead of json object – Vivek Mishra Jun 30 '16 at 07:45
i have edit the jsonformat in my code is this correct or wrong? – ss ss Jun 30 '16 at 07:51
it is wrong. I said to make restaurants a json array . Do not put it in another json object – Vivek Mishra Jun 30 '16 at 07:57
why are you not removing json object that is before restaurants?? – Vivek Mishra Jun 30 '16 at 08:29
I can't get the clear idea what ur telling – ss ss Jun 30 '16 at 08:39
don't put restaurants inside a json object . put it simply in json array . something like this `[restaurants{}]` – Vivek Mishra Jun 30 '16 at 08:40

How to get the Json format in android

1 Answers1