Regular Expression accepting only 9 digits, no special characters , not all zero's and should not start with zero

Question

Hi i need a Regular Expression which is accepting only Numbers from 0-9 ,but should not contain all Zeros ,should not contain special characters , should not start with zero and with a length of exact 9 digits.

I tried this one but it is accepting special characters at last. ^[1-9][0-9]{8}

Please help me out. Thanks in advance.

score 2 · Answer 1 · answered Jun 30 '16 at 14:11

Have you tried

^[1-9]\d{8}$

Not sure why you are seeing special characters at the end unless it's after the 9 digits. the $ will solve that problem.

Additionally I prefer the use of character classes when applicable (\d for any digit). I think it makes, sometimes very complicated, Regex easier to read than groups.

score 2 · Accepted Answer · answered Jun 30 '16 at 14:11

2

Put a ending character at the end $

 ^[1-9][0-9]{8}$

answered Jun 30 '16 at 14:11

C14L

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i have one more requirement can you please provide a solution for my requirement, My requirement is A regular expression that may accept leading zero's only up to 2 Regular expression should accept 012312312 001231231 123123123 these 3 patterns. Please help me out.. – Meena Mar 09 '17 at 08:08
`^(?!000)[0-9]{9}$` That should probably do it. It uses a look-around at the first position to make sure there is no "000" there. More on [negative matching is in this answer](http://stackoverflow.com/a/5334825/5520354) – C14L Mar 11 '17 at 11:33

score 0 · Answer 3 · answered Jun 30 '16 at 14:13

0

Try this change

^[1-9]\d{8}

I hope it works

answered Jun 30 '16 at 14:13

Adolfo

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Regular Expression accepting only 9 digits, no special characters , not all zero's and should not start with zero

3 Answers3