Python if statement no cap check

Question

I have a input that the user types in something Example

Test = input( 'Type in something' )
if Test == 'SOMETHING' :
    print( 'You idiot!' )

How do I ignore the if the word something is in all caps or non caps example: Something SOMETHING SoMeThinG

Sorry My Grammar is so bad It's hard to word these things

@Adriaan It's caused by a very rare bug in SOUP :/ – DavidPostill Apr 04 '17 at 22:04 — DavidPostill, Apr 04 '17 at 22:04

score 0 · Answer 1 · answered Jul 02 '16 at 13:35

0

Just make everything lowercase and strip whitespace

Test.lower().strip()

Provided SOMETHING is in lowercase.

answered Jul 02 '16 at 13:35

ifma

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score 0 · Accepted Answer · answered Jul 02 '16 at 13:35

if Test.upper() == "something".upper(): print("You idiot")

What about making the two parts of the equatation upper/lower?

Python 3.5.2 (v3.5.2:4def2a2901a5, Jun 25 2016, 22:01:18) [MSC v.1900 32 bit (Intel)] on win32
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>>> Test = input("type in something ")
type in something SomeTHING
>>> Test.upper() == "something".upper()
True
>>>

Python if statement no cap check

2 Answers2