How to replace all existence of chars from string in jquery?

Question

I want to replace all existence of chars from a string, but it is not working. here is my code:

 $.each(jsonArray, function (fromString, jtm) {
   // tempString = tempString.replace(jtm.from, jtm.to)
   tempString = tempString.replaceAll(jtm.from, jtm.to);
 });

I checked to use global to replace all as Told in this article but i am not getting how i can implement in my code.

Please help me.

`tempString = tempString.replace(new RegExp(jtm.from,'g'), jtm.to)` — Pranav C Balan, Jul 05 '16 at 05:23
`tempString = tempString.replace(new RegExp(jtm.from.replace(/[|\\{}()[\]^$+*?.]/g, '\\$&'),'g'), jtm.to)` — Pranav C Balan, Jul 05 '16 at 05:26

score 3 · Accepted Answer · edited May 23 '17 at 12:22

In javascript there is no method like replaceAll(), to remove all occurrence you need to use regex with global flag.

tempString = tempString.replace(new RegExp(jtm.from,'g'), jtm.to);

In case string contains characters which have special meaning in regex then escape them first.

tempString = tempString.replace(new RegExp(jtm.from.replace(/[|\\{}()[\]^$+*?.]/g, '\\$&'),'g'), jtm.to)

Refer : Converting user input string to regular expression

How to replace all existence of chars from string in jquery?

1 Answers1