C# bitwise shift on ushort (UInt16)

Question

I need to perform a bitwise left shift on a 16-bit integer (ushort / UInt16), but the bitwise operators in C# seem to apply to int (32-bit) only. How can I use << on an ushort, or at least get to the same result with a simple workaround?

score 19 · Accepted Answer · answered Sep 29 '10 at 07:34

19

Cast the resulting value back into ushort after shifting:

ushort value = 1;
ushort shifted = (ushort)(value << 2);

answered Sep 29 '10 at 07:34

driis

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will `value` be implicitly converted to `uint` for the `<<` operator? – xtofl Sep 29 '10 at 07:39
almost embarrassing, so simply this was :) I did almost the same, but forgot the brackets around (value << 2) – KBoek Sep 29 '10 at 07:41
@xtofl, value will be implicitly converted to int. – driis Sep 29 '10 at 07:42
@xtofl, `int` as @driis says. Note also that in this case, and many similar cases, the result will be the same either way. – Jon Hanna Sep 29 '10 at 08:36

C# bitwise shift on ushort (UInt16)

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