When I prepare my program for deployment, I pack it into a JAR, along with the Eclipse jar-in-jar class loader. When my program runs from the JAR, I need to know a package's version, but I can not obtain it from the jar's manifest a simple and "honest" way. The manifest looks like this:
Manifest-Version: 1.0
Created-By: 1.8.0_73-b02 (Oracle Corporation)
Main-Class: org.eclipse.jdt.internal.jarinjarloader.JarRsrcLoader
Rsrc-Main-Class: com.domain.sp2.controller.Controller
Rsrc-Class-Path: ./ jar-in-jar-loader.zip javahelp-2.0.05.jar json-simple-1.1.1.jar
Class-Path: .
Name: com/domain/sp2/controller/
Implementation-Version: 19
To obtain the package's implementation version, I try to use the simplest and straight-forward way:
package com.domain.sp2.controller;
public class Controller {
...
public static String getBuildNumber() throws IOException {
Package pckg = Controller.class.getPackage();
pr(pckg.getName()); // prints "com.domain.sp2.controller", as expected
return pckg.getImplementationVersion(); // returns null
}
...
}
According to http://docs.oracle.com/javase/tutorial/deployment/jar/packageman.html and http://docs.oracle.com/javase/8/docs/api/java/lang/Package.html#getImplementationVersion-- (and other sources), it should return "19", but it returns null. For the packages of the JRE libraries, it returns correct values. Perhaps I have missed a detail about how to name the package in the manifest, or the reason pertains to the JarRsrcLoader
- may be it requires some special syntax to address packages. I have also tried ".com/domain/..."
, "/com/domain/..."
and ".../controller"
, and even "rsrc:./com/domain..."
as the package name in the manifest - all without success. I could use other ways, e.g. to load the manifest as stream and parse it with the Manifest class, yet I would like to understand what is the correct way to use the getImplementationVersion()
method.