Need to get words at "even" indices from string

Question

Here is a string as an example.

s = 'asdf df d f d ssa'.

I need to get words at even indices from a string. For the above string s, the words are:

1. 'asdf'
2. 'df'   // Even index
3. 'd'
4. 'f'    // Even index
5. 'd'
6. 'ssa'  // Even index

A correct output would be 'df f ssa'. I think I would do this with a slice.

How might I go about this?

We're not going to do your homework for you. If you have some code that you've written that you're having an issue with, and you've read [help] and [mcve], feel free to ask a new question. — Morgan Thrapp, Jul 05 '16 at 18:20
Check out [Explain Python's Slice Notation](http://stackoverflow.com/questions/509211/explain-pythons-slice-notation.) — Michael Molter, Jul 05 '16 at 18:23
Honestly, looking at the example, I still don't know what the OP is asking. Maybe this is actually a unique request, and we just need a few more examples to understand it. — Michael Molter, Jul 05 '16 at 18:28

score 3 · Accepted Answer · answered Jul 05 '16 at 18:21

3

You meant words at even indices (if that sounds correct). split and then slice with a step of 2 starting at 1:

>>> ' '.join(s.split()[1::2])
'df f ssa'

Your even would mean odd here, since indexing starts from zero.

answered Jul 05 '16 at 18:21

Moses Koledoye

1 Answers1