Compile c struct to bin file

Question

I have a C file:

#include <stdint.h>

typedef struct {
  uint32_t m1;
  uint16_t m2;
} TStruct;

TStruct s = {
  1,
  2
};

How to compile this file with gcc to produce little endian binary file?

0x01 0x00 0x00 0x00 0x02 0x00

compile it for an arch that uses little endian... and you also have to take care of alignment. — LPs, Jul 06 '16 at 15:34

score 0 · Answer 1 · answered Jul 06 '16 at 15:47

0

Though, Little-Endian is the default for all standard configurations. A otherwise configured compiler toolkit can use this switch to fetch desired format.

    gcc file.c -mlittle-endian

There you go..

answered Jul 06 '16 at 15:47

Amit Kumar

59
1
8

score 0 · Answer 2 · answered Jul 06 '16 at 15:55

I guess tying together the other answers. On a little endian machine (x86):

evaitl@evbb ~/se $ cat foo.c 
#include <stdint.h>

typedef struct {
  uint32_t m1;
  uint16_t m2;
} TStruct;

TStruct s = {
  1,
  2
};
evaitl@evbb ~/se $ gcc -c foo.c 
evaitl@evbb ~/se $ objcopy -O binary foo.o  foo
evaitl@evbb ~/se $ hexdump -C foo
00000000  01 00 00 00 02 00 00 00                           |........|
00000008

score -1 · Answer 3 · edited May 23 '17 at 12:08

-1

Probably

objcopy -O binary

is what you are looking for.See [ this ] SO answer.

edited May 23 '17 at 12:08

Community

1
1

answered Jul 06 '16 at 15:35

Sergio

8,099
2
26
52

Compile c struct to bin file

3 Answers3