I'm still new to python, and have started with pygame. I'm making an endless runner game, but I've run into a problem with my run cycle. Here's my code:
import pygame
import sys
from pygame.locals import *
pygame.init()
clock = pygame.time.Clock()
clock2 = pygame.time.get_ticks()
screen = pygame.display.set_mode((640, 575))
bgx = 0
bgx2 = -800
scroll = 10
pose = 1
background = pygame.image.load("images/background2.png").convert_alpha();
player = pygame.image.load("images/character1.png").convert_alpha();
screen.blit(background, (0, 0))
def draw_screen(x):
screen.blit(background, (x, 0))
def draw_screen2(x2):
screen.blit(background, (x2, 0))
def draw_player(pose):
if pose == 1:
player = pygame.image.load("images/character1.png").convert_alpha();
screen.blit(player, (0, 0))
elif pose == 2:
player = pygame.image.load("images/character2.png").convert_alpha();
screen.blit(player, (0, 0))
elif pose == 3:
player = pygame.image.load("images/character3.png").convert_alpha();
screen.blit(player, (0, 0))
elif pose == 4:
player = pygame.image.load("images/character2.png").convert_alpha();
screen.blit(player, (0, 0))
def set_poses(pose):
if pose == 1:
pose = 2
if pose == 2:
pose = 3
if pose == 3:
pose = 4
if pose == 4:
pose = 1
while True: #Loop
clock2 = pygame.time.get_ticks()
#Quitting Function
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
quit()
clock.tick(50)
#Screen Scrolling
if bgx != 800:
bgx += scroll
else:
bgx = 0
if bgx2 != 0:
bgx2 += scroll
else:
bgx2 = -800
#Drawing Items
draw_screen2(bgx2)
draw_screen(bgx)
draw_player(pose)
if clock2%6 == 0:
set_poses(pose)
pygame.display.update()
So the screen is scrolling, and my character appears but he stays in his first position (Frame I guess.) at the part where it runs set_poses(pose)
I tried having it also print something right before setting the pose, which it did, but its not setting the pose. I tried having it printing the pose, and it showed that the poses wasn't changing. So, yea, I've found my problem, but I can't for the life of me find a solution.