Get Float part in Int

Question

I am developing an app in which i have to get the float part in terms of integer value.

for example if my number is 153.12324 then output should be 12324.I tried this way but it works wrong some time.

What's the problem in this or is there a better way to do this ?

there is a double value in d

    double d =any_double_value;
    String[] splitter = String.valueOf(d).split("\\.");
    splitter[0].length();   // Before Decimal Count
    int count = splitter[1].length();
    int integerpart = (int) calcResult;
    double floatpart = calcResult - integerpart;
    while (count!=0)
    {
        floatpart=floatpart*10;
        count--;
    }

    int floatpartinInt=(int)floatpart;

this works wrong only in some cases(it gives 1 number less, like if answer is 124 it gives 123) and in cases where answer is long double no like 3.333333333 (10/3)

A wonderful mistake: 1.00023 and 1.000229 will give 23 and 229. Floating point is a rough approximation and has no precise number of digits as string. — Joop Eggen, Jul 07 '16 at 07:20

score 3 · Answer 1 · answered Jul 07 '16 at 07:12

3

You can also without split. by using following way,

double value = 3.25;
double fractionalPart = value % 1;
double integralPart = value - fractionalPart;

This may helps you

answered Jul 07 '16 at 07:12

Sathish Kumar J

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score 0 · Answer 2 · answered Jul 07 '16 at 07:11

0

Use this code its work in your case and enjoy Man

double val=1.9;
    String[] arr=String.valueOf(val).split("\\.");
    int[] intArr=new int[2];
    intArr[0]=Integer.parseInt(arr[0]); // 1
    intArr[1]=Integer.parseInt(arr[1]); // 9

answered Jul 07 '16 at 07:11

Nitesh Pareek

362
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score 0 · Answer 3 · answered Jul 07 '16 at 07:16

0

You could also do this:

lvalue = (long) value;
fPart = value - lvalue;

answered Jul 07 '16 at 07:16

wake-0

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Get Float part in Int

3 Answers3