Migration from swift2 to swift3 and changes for advanceBy for Range

Question

There is a function

func find(... rangeString1: Range<String.Index>, ...) ...

and this function has in swift2

while i >= minimalIdentity{

var first = rangeString1.startIndex
var last = first.advancedBy(i, limit: rangeString1.endIndex)
...

Question is how should look the

var last

in swift3

var first = rangeString1.lowerBound
var last =

Related: http://stackoverflow.com/questions/38070273/cant-create-a-range-in-swift-3. — Martin R, Jul 08 '16 at 04:48
@Martin R Thanks. Is there swift 2 analog of last for range in swift3. I see only upperBound, but it is analog of endIndex in swift2 ? — VYT, Jul 08 '16 at 08:09
Yes, as I mentioned in that answer, start/endIndex have been renamed to lower/upperBound. — Martin R, Jul 08 '16 at 08:10
@Martin R Sorry, I mean - let last = range!.last which gives index lower on 1 unit than - let end = range!.endIndex. — VYT, Jul 08 '16 at 08:14
Swift 3 has `Range` and `CountableRange`. The latter is a collection and has a `last` property. — Martin R, Jul 08 '16 at 09:18
@Martin R If I am trying initialise range as CountableRange (instead of Range in swift2) compiler is complaining that index is not confirm to protocol Strideable — VYT, Jul 08 '16 at 09:50
@Martin R So, I have problem not only with .last for range for string (I can use indirect way with offsetBy, aka advanceBy to get the last value). But, I also cannot get count from range, and I don't have idea how to get it. Do you have an idea how to get count from range? — VYT, Jul 08 '16 at 10:04
Here is another example for Swift 3: http://stackoverflow.com/a/38228514/1187415. In Swift 3 you always need the original collection to perform calculations with its indices. — Martin R, Jul 08 '16 at 13:37

Tim Vermeulen · Accepted Answer · 2016-07-07T22:34:18.833

1

Whatever string those indices belong to is responsible for this in Swift 3:

let first = rangeString1.lowerBound
let last = myString.index(first, offsetBy: i, limit: rangeString1.upperBound)

edited Jul 07 '16 at 22:34

answered Jul 07 '16 at 21:59

Tim Vermeulen

I cannot use rangeString1.index, compiler is saying that Range has no member index – VYT Jul 07 '16 at 22:11
Oh sorry, I thought that was your string. You basically need to call it on the string that the indices belong to, see my edit. – Tim Vermeulen Jul 07 '16 at 22:33
If I need string that is bad feature of swift3 in comparison with swift2. So, I have to make substring for Range and then can use it, while in swift2 I could use directly the Range. – VYT Jul 07 '16 at 22:43
Yeah, you'll need the string that the indices belong to. – Tim Vermeulen Jul 07 '16 at 22:48
Thanks for the explanation! – VYT Jul 07 '16 at 22:51

score 0 · Answer 2 · answered Jul 07 '16 at 21:34

0

var last = rangeString1.endIndex

answered Jul 07 '16 at 21:34

Alexander

I cannot, I need advanceBy for iteration in while loop – VYT Jul 07 '16 at 21:39
Ah okay, well in that case I see someone already mentioned [`index(_:offsetBy:limit:)`](https://developer.apple.com/reference/foundation/indexpath/1780097-index) – Alexander Jul 08 '16 at 14:27

2 Answers2