What is difference between 2 string literals

Asked Jul 08 '16 at 07:15

Active Jul 08 '16 at 07:24

Viewed 62 times

I have one String literal which refers to a string pool reference

String s1 = "abc";

Suppose i create/assign a new String literal like:

String s2 = s1 + "pqr";

Which of the following will happen?

change contain of existing string pool object.
create new object in string pool and assign to s2, if yes then what is the size of s2;

edited Jul 08 '16 at 07:19

raphaëλ

asked Jul 08 '16 at 07:15

Gabu

2

The value assigned to `s2` is not in the string pool, unless you declare `s1` to be `final`. – Andy Turner Jul 08 '16 at 07:19
1

And "change contain of existing string pool object." will definitely not happen, ever. Strings are immutable. – Andy Turner Jul 08 '16 at 07:21
1

Deepest and most comprehensive answer: http://stackoverflow.com/a/29978564/14637 – Thomas Jul 08 '16 at 07:31
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The correct answer is 'neither'. – user207421 Jul 08 '16 at 07:32
I don't think this question is a duplicate of the referred question. That was about creating a String within and outside of String literal pool. This is about creating a String within the String Literal pool and then create an another from this String. – Igorovics Jul 08 '16 at 07:41
Any one can tell me what is the memory allocation of 'S2'. – Gabu Jul 08 '16 at 08:40
I think this would be useful for you: http://www.xyzws.com/javafaq/what-is-string-literal-pool/3 – Igorovics Jul 08 '16 at 09:28
@Gabu `s2` is allocated in the heap. – user207421 Jul 09 '16 at 04:10
@Igorovics So it is a duplicate of another of the 10,000 questions here on the topic. – user207421 Jul 09 '16 at 04:10

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