Regex - expression error not able to get correct result

Question

Here's my code,

new_name = re.sub(r'[^A-Z a-z]', '', new_name)
new_name += '.txt'

Input: new_name = "Air Supply 85' [1985]"

Output what I am getting: "Air Supply .txt"

It is recognizing the extra spaces too from ' 85' [1985]' But I want it to end the new_name as character only as 'Air Supply.txt'

score 1 · Accepted Answer · edited May 23 '17 at 12:32

1

Trim the whitespace with .strip()

new_name = re.sub(r'[^A-Z a-z]', '', new_name).strip()
new_name += '.txt'

edited May 23 '17 at 12:32

Community

answered Jul 08 '16 at 19:12

Tori Huang

@YashAgarwal `strip()` would remove the space characters from the sides of a string only. – alecxe Jul 08 '16 at 19:21
@alecxe Thanks for clarifying it for me, I did not know that. – Yash Agarwal Jul 08 '16 at 19:25

1 Answers1