supposed that 'a' through 'j' represent 0 to 9 in your mother language and numbers are written left to right.
it's better if you convert the input and output to normal integers and work with them. because this way you have access to all Mathematical methods that java provides and more important java's libraries are more robust than your own methods.
this two method will convert String object(your wanted characters to int)
to int and Vice versa.
public static String convertToString (int value){
StringBuilder result = new StringBuilder();
for (int i=1;value/i>0;i *= 10)
switch( value % (i*10) / i){
case 0:
result.append('a');
break;
case 1:
result.append('b');
break;
case 2:
result.append('c');
break;
case 3:
result.append('d');
break;
case 4:
result.append('e');
break;
case 5:
result.append('f');
break;
case 6:
result.append('g');
break;
case 7:
result.append('h');
break;
case 8:
result.append('i');
break;
case 9:
result.append('j');
break;
}
return result.reverse().toString();
}
public static int convertToInt(String string){
int result = 0;
int j =1;
for (int i=string.length()-1;i>=0;i--,j *= 10)
switch(string.charAt(i)){
case 'b':
result += 1*j;
break;
case 'c':
result += 2*j;
break;
case 'd':
result += 3*j;
break;
case 'e':
result += 4*j;
break;
case 'f':
result += 5*j;
break;
case 'g':
result += 6*j;
break;
case 'h':
result += 7*j;
break;
case 'i':
result += 8*j;
break;
case 'j':
result += 9*j;
break;
}
return result;
}