Missing Operator in a `for` loop

Question

I've started to write a brainfuck compiler in bash.
The 'compiler' translates the code in assambly to compile it using gcc.
The problem is, when I try to run it, it prints this error:

$ ./compiler test.bf
./compiler: Zeile 111: src: {0..45}: Syntax Fehler: Operator erwartet. (Fehlerverursachendes Zeichen ist \"{0..45}\").

(In english:

$ ./compiler test.bf
./compiler: Line 111: src: {0..45}: Syntax Error: Operator excepted. (Causal Error Char is \"{0..45}\").

)

As I might understand, It says that there is a fault in line 111:

...
for i in {0..${#src}}        # line 109
do                           # line 110
    case ${src:$i:1} in      # line 111
...

(Here is the full code)

But I don't see any.

If the error is cause of the for loop, can you tell me how to make a for loop like in python:

for i in range(15):
    ...

Thanks in advance

score 1 · Accepted Answer · answered Jul 12 '16 at 19:42

1

Use the C-style for loop:

for ((i=0; i < ${#src}; i++)); do

answered Jul 12 '16 at 19:42

chepner

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Thanks for this answer, it helped a lot ^^ – caffeinated-fox Jul 12 '16 at 19:53

Aaron · Answer 2 · 2016-07-12T20:07:49.820

0

You can't use variables inside the {m..n} construct ; use seq instead :

for i in $(seq 0 ${#src})# line 109
do                       # line 110
    case ${src:$i:1} in  # line 111

edited Jul 12 '16 at 20:07

answered Jul 12 '16 at 19:39

Aaron

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Missing Operator in a `for` loop

2 Answers2