Getting text after a match from stdout

Question

I want to extract the next word/number after specific words I find using grep or whatnot.

As an example lets say this is what I have in stdout

string-a0 match-a1 string-a2 string-a3
string-b0 string-b1 match-b2 string-b3
match-c0 string-c1 string-c2 string-c3

I want to be left with just this

string-a2
string-b3
string-c1

mind that match-a1 != match-b2 != match-c0

EDIT

A concrete example...

stdout is this

open 0.23 date ...
close 1.52 date ...
open 2.34 date ...
close 5.92 date ...
open 10.78 date ...
close 24.21 date ...
total 45.3

I'm searching for the words open, close and total so the output should be

Could you elaborate your matching condition? Or a better example of what you are trying to do? — Michelle Tan, Jul 13 '16 at 13:40
I don't know bash, but I imagine the regex would be `match-[abc][012] (\S+)` and grab the first capture group. — 4castle, Jul 13 '16 at 13:46
A simple `\b(\d+\.\d+)\b` just grabbing a decimal number? [Check it out here](https://regex101.com/r/gW2aZ4/1). — SamWhan, Jul 13 '16 at 13:49
Are 'open', 'close', 'total' always in first column? From your first example i thoughd that it may vary. — Arnial, Jul 13 '16 at 13:51
@123 this is not a duplicate of the question you guys tagged since I have a **set of words** I need to match against where's the other question requires only a single match. It might be trivial for those basking in bash and awk glory but unfortunately I'm not there yet. — Yoni Levy, Jul 13 '16 at 14:12
@YoniLevy I did not vote to close as duplicate. I voted to close as unclear what you are asking. — 123, Jul 13 '16 at 14:14
@123 well... I have 2 examples with 2 quick answers that got it right so I guess someone found it clear. — Yoni Levy, Jul 13 '16 at 14:20

William Pursell · Accepted Answer · 2016-07-13T13:54:59.973

2

This doesn't match the general case, but works for your example:

awk '/^open|^close|^total/{print $2}' input

For the general case, if your definition of "string" is based on whitespace, perhaps you want:

tr -s ' \n' \\n < input | awk 'p{print; p=0} {p=/^open|^close|^total/}'

edited Jul 13 '16 at 13:54

answered Jul 13 '16 at 13:49

William Pursell

1

isn't $2 index specific? I don't necessarily know the location of the next word (index-wise), this is why I put the generic case with `string-*` and `match-*`. Notice how the match position differs – Yoni Levy Jul 13 '16 at 13:52

score 1 · Answer 2 · answered Jul 13 '16 at 13:55

1

You can use this awk for printing next word after the search word:

awk -v s='^(open|close|total)$' '{for (i=1; i<NF; i++) if ($i ~ s) print $(i+1)}' 

0.23
1.52
2.34
5.92
10.78
24.21
45.3

answered Jul 13 '16 at 13:55

anubhava

2 Answers2