How to find nearest bigger 2**n value to a value?

Question

My goal is to get nearest bigger number than an input integer that is two to the n.

For example, what should nearestbigger be?

integerinput = [2016, 300, 9001]
for x in integerinput:
    print(nearestbigger(x))

Expected Output

2048
512
16384

I've reopened this question because OP is seeking a python soluiton, whereas the so-called duplicate is cross-language, and in fact there is now python solution there. — shx2, Jul 17 '16 at 18:13

score 1 · Accepted Answer · answered Jul 16 '16 at 20:37

1

def nearesbigger(n):
    if n <= 0:
        return 1
    return 2 ** (n-1).bit_length()

answered Jul 16 '16 at 20:37

shx2

1 Answers1