Exception when create zipFile in Android with Zip4j: Probably not a zip file or a corrupted zip file

Question

I meet a problem when using zip4j library to generate zipfile in android, here's the code :

try {
    ZipFile zipFile = new ZipFile(dest);
    zipFile.setFileNameCharset("GBK");
    if (srcFile.isDirectory()) {
        zipFile.addFolder(srcFile, parameters);
    } else {
        zipFile.addFile(srcFile, parameters);
    }
} catch (Exception e) {
    e.printStackTrace();
}

and I got the Exception msg:

    net.lingala.zip4j.exception.ZipException: Probably not a zip file or a corrupted zip file
    at net.lingala.zip4j.core.HeaderReader.readEndOfCentralDirectoryRecord(HeaderReader.java:179)
    at net.lingala.zip4j.core.HeaderReader.readAllHeaders(HeaderReader.java:78)
    at net.lingala.zip4j.core.ZipFile.readZipInfo(ZipFile.java:425)
    at net.lingala.zip4j.core.ZipFile.checkZipModel(ZipFile.java:935)
    at net.lingala.zip4j.core.ZipFile.addFiles(ZipFile.java:263)
    at net.lingala.zip4j.core.ZipFile.addFile(ZipFile.java:250)
Caused by: java.io.IOException: Negative seek offset
    at java.io.RandomAccessFile.seek(RandomAccessFile.java:555)
    at net.lingala.zip4j.core.HeaderReader.readEndOfCentralDirectoryRecord(HeaderReader.java:117)

This code works perfect in Eclipse for local files, but does not work well in Android, I'm pretty sure the destination .zip path is correct, and the zip4j library version is 1.3.2.

could anyone give me any suggestion?

score 7 · Accepted Answer · answered Nov 16 '16 at 17:00

I came across very similar stacktrace. However, I use java and zip4j in version 1.3.2 on desktop. I am not sure how my answer is relevant to android but here it goes.

My stacktrace

Caused by: net.lingala.zip4j.exception.ZipException: Probably not a zip file or a corrupted zip file
        at net.lingala.zip4j.core.HeaderReader.readEndOfCentralDirectoryRecord(HeaderReader.java:179)
        at net.lingala.zip4j.core.HeaderReader.readAllHeaders(HeaderReader.java:78)
        at net.lingala.zip4j.core.ZipFile.readZipInfo(ZipFile.java:425)
        at net.lingala.zip4j.core.ZipFile.checkZipModel(ZipFile.java:935)
        at net.lingala.zip4j.core.ZipFile.addFolder(ZipFile.java:343)
        at net.lingala.zip4j.core.ZipFile.addFolder(ZipFile.java:330)
Caused by: java.io.IOException: Negative seek offset
        at java.io.RandomAccessFile.seek(RandomAccessFile.java:555)
        at net.lingala.zip4j.core.HeaderReader.readEndOfCentralDirectoryRecord(HeaderReader.java:117)
        at net.lingala.zip4j.core.HeaderReader.readAllHeaders(HeaderReader.java:78)

I use zip4j like this

Path destination = Files.createTempFile("export", ".zip");
ZipFile zip = new ZipFile(destination.toFile());

To fix the problem I changed to

File destination = new File(System.getProperty("java.io.tmpdir"), UUID.randomUUID().toString());
ZipFile zip = new ZipFile(destination);

The difference is Files.createTempFile() creates empty file and the file must screw up ZipFile's constructor. When I passed File with unoccupied path, the problem was gone.

score 0 · Answer 2 · answered Dec 28 '21 at 05:14

The working code for this along with the password protected zip is :

File dbFile = new File(ctx.getExternalFilesDir("") + File.separator +
                        AppConstants.DB_PATH + File.separator + AppConstants.DB_NAME);
zipName = AppConstants.DB_NAME + "-" + getCurrentDateTime() + ".zip";
ZipFile zipFile = new ZipFile(folderPath + File.separator + zipName);

ZipParameters parameters = new ZipParameters();
parameters.setCompressionMethod(Zip4jConstants.COMP_DEFLATE);
parameters.setCompressionLevel(Zip4jConstants.DEFLATE_LEVEL_NORMAL);
parameters.setEncryptFiles(true);
parameters.setEncryptionMethod(Zip4jConstants.ENC_METHOD_AES);
parameters.setAesKeyStrength(Zip4jConstants.AES_STRENGTH_256);
parameters.setPassword(AppUtil.decodeStr(AppConstants.DB_PASSWORD));
zipFile.addFile(dbFile, parameters);

However the issue may still appear because of the following reasons:

Either the source file does not exists while adding to zipFile,
The app do not have permissions to read the source file,
The target zip file might consist of special symbols or space in the file name.

score -1 · Answer 3 · edited Jul 24 '17 at 10:48

-1

I met with the same question because of I used AES encryption but didn't set the parameters AES data key.

edited Jul 24 '17 at 10:48

Pravitha V

3,308
4
33
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answered Jul 24 '17 at 09:42

xiaotianrou

9

2

Please **[edit]** your post and show the actual code as text instead of screenshots. Others can't copy and paste from your images. [See here](https://meta.stackoverflow.com/a/285557/1402846) for details. Thank you. – Pang Jul 24 '17 at 09:48

Exception when create zipFile in Android with Zip4j: Probably not a zip file or a corrupted zip file

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