This questions been asked a number of times but the answers given are ALL GNU sed specific.
sed -i '' "/${FIND}/,+2d" "$FILE"
Gives a "expected context address" error.
Please could someone give me an example of how to use BSD sed to delete X lines including the match and another X lines excluding the match?
The problem is that this is simply not a job for sed, it's job for awk.
$ seq 5 | awk '/3/{c=2} !(c&&c--)'
1
2
5
Just set the variable c to however many lines you want to skip.
The following sed editing script (run with -n) will emulate what GNU sed /^pattern/,+2d does:
/^pattern/{
n
n
d
}
p
When matching /^pattern/, it will read the next two lines of input, and then discard everything (restarting the cycle). When the pattern doesn't match, the line is printed.
