Strange result of re.match()

Question

`

t='1111 si debiteur'
import re
re.match(r"si débiteur",t) is None #gives back True as a result
re.match(r"1111 si débiteur",t) is None #gives back True as a result
re.match(r"1111 si débiteur",t) is not None #gives back False as a result
t='8588'
re.match(r"1111 si débiteur",t) is None #gives back True as a result

`

the thing is i don't really get why "re.match(r"1111 si débiteur",t) is None" returning True in both case

Missing the acute in your original string? Try `1111 si débiteur` instead of `1111 si debiteur` — Marwie, Jul 21 '16 at 09:43
See also [Regex - match a character and all its diacritic variations (aka accent-insensitive)](/http://stackoverflow.com/q/35783135/3688648) — Felk, Jul 21 '16 at 10:14

score 1 · Answer 1 · answered Jul 21 '16 at 09:37

1

The value of t: 1111 si debiteur does not have an accent. Where re.match(r"1111 si débiteur",t) does.

answered Jul 21 '16 at 09:37

RvdK

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aaaaah that was really stupid of me , thanks soo much i've been stuck in this for too long :D – unholy spider Jul 21 '16 at 09:38

Strange result of re.match()

1 Answers1