1 not equal to 0 but the code says equal in c

Question

This code prints both "equal" and "1 0".

Why is this happening even though 1 != 0 ?

if(2/2 == 2/2.0) 
    printf("equal \n");

printf("%d  %d", 2/2, 2/2.0);

Undefined behavior, you can't use `%d` for a double – Mat Jul 22 '16 at 07:47 — Mat, Jul 22 '16 at 07:47
Related: http://stackoverflow.com/q/2100490/694576 – alk Jul 22 '16 at 08:53 — alk, Jul 22 '16 at 08:53

score 5 · Answer 1 · edited Jul 22 '16 at 08:48

5

The result of 2/2.0 is of type double. But you are using %d to print it, which is undefined behaviour. Use %lf instead to print a double. That's why you get 0 which is a possible result of invoking undefined behaviour.

edited Jul 22 '16 at 08:48

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answered Jul 22 '16 at 07:47

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1 not equal to 0 but the code says equal in c

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