Removing period from number in python

Question

Given a real number between 0 and 1 (for example 0.2836) I want to return only the number without the dot (for example in this case from 0.2836 -> 2836 or 02836). I was trying to use python to do this but I just started and I need some help.

Show what you have tried. (and you mean *period*, not comma) — Idos, Jul 23 '16 at 17:25
I haven't tried anything because I don't know where to begin — PunkZebra, Jul 23 '16 at 17:26
*What have you tried* to read on the Python documentation, then? — OneCricketeer, Jul 23 '16 at 17:29
I'd also done 'int(str(number).replace('.', ''))' but I searched for other ways and I found this function of the _math_ module that may interests you http://stackoverflow.com/questions/6681743/splitting-a-number-into-the-integer-and-decimal-parts-in-python — Stéphane, Jul 23 '16 at 17:37

Moses Koledoye · Answer 1 · 2016-07-23T17:33:12.863

5

As long as you have a number, the following should do:

>>> number = 0.2836
>>> int(str(number).replace('.', ''))
2836

If a . is not found in the string, str.replace just returns the original string.

With more numbers:

>>> int(str(1).replace('.', ''))
1
>>> int(str(1.2).replace('.', ''))
12

edited Jul 23 '16 at 17:33

answered Jul 23 '16 at 17:27

Moses Koledoye

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As far as I can see the command works with numbers with less than 12 digits after the comma, is there a way to have more digits returned? – PunkZebra Jul 23 '16 at 17:35
@Peterix [Floating Point Arithmetic: Issues and Limitations](https://docs.python.org/3/tutorial/floatingpoint.html#floating-point-arithmetic-issues-and-limitations) – Moses Koledoye Jul 23 '16 at 17:46

score 0 · Answer 2 · answered Jul 23 '16 at 17:31

The simplest way to remove an unwanted character from a strip is to call its .replace method with an empty string as the second argument:

x = str(123.45)
x = x.replace('.','')
print(x)                 # Prints 12345

Note, this would leave any leading zeros (i.e. 0.123 using this method would result in 0123)

If you know there are always, say, 4 numbers after the decimal (and in the case that there are less, you want trailing zeros), you could multiply the number by an appropriate factor first:

x = 123.4567
x *= 10000
x = str(int(x))          # Convert float to integer first, then to string
print(x)                 # Prints 1234567

There are other options, but this may point you in the right direction.

Removing period from number in python

2 Answers2