Why is this simple php form not posting?

Question

It's as simples as a form can get. However, it's not working at all.

The HTML form:

 <body>
    <form method="POST" action="porra.php">
         <div id="refeicao">
                <h1>Segunda</h1>
            Café da manhã
            <br><input name="Cafe da manhã-quantidade-0" type="number" min="0" placeholder="un." />
<input type="submit" name="submit"/>
    </form>
    <script src="gerar_cardapio_js.js" language="Javascript" type="text/javascript"></script>
    </body>

The PHP code (page "porra.php"):

<?php
$var = $_POST["Cafe da manhã-quantidade-0"];
?>

However, i get this error after submission:

Notice: Undefined index: Café da manhã-quantidade-0 in C:\xampp\htdocs\cardapio\porra.php on line 2

Can someone please make this work?

EDIT:

I edited the code to correct a typo and to elimnate code that I was not using for this question.

input name="Cafe da manhã-quantidade-0" deosnt have a value — mujuonly, Jul 24 '16 at 18:16
I use this page to correct erros in my code. So, it expresses my anger haha — Pedro Martins Novaes, Jul 24 '16 at 18:16
Majeebu Rahman, I made this change: But it's not working still. — Pedro Martins Novaes, Jul 24 '16 at 18:18
Please, run `var_dump($_POST);` so you can see the keys and values... — FirstOne, Jul 24 '16 at 18:20
You have to access it like this: `$_POST['Cafe_da_manhã-quantidade-0']`. Take a look at [this answer](http://stackoverflow.com/a/13858670/4577762). If you check the result from my previous comment, you'll see that spaces have been converted to `_` (at least when I tested it) — FirstOne, Jul 24 '16 at 18:22
Why don't you just use an easier variable than "Cafe da manhã-quantidade-0"? This might be making you a bit confused from your native language portuguese, to coding. — Farini, Jul 24 '16 at 18:42
FirstOne, as suggested by many, I'm not going to use non-ascii charaters. That did it for me, thank you! — Pedro Martins Novaes, Jul 24 '16 at 18:42

score 1 · Answer 1 · answered Jul 24 '16 at 18:17

1

The form has the input index set to "Cafe da manhã-quantidade-0"

The php script is looking for "Café da manhã-quantidade-0"

It might be worth using plain ascii to avoid this problem entirely, something like "quantity"

answered Jul 24 '16 at 18:17

z1ad

88
1
5

That was a typo for sure, I changed the code but it's not working still. However, I'll edit the original post to correct that. Ty. – Pedro Martins Novaes Jul 24 '16 at 18:21
Try without the spaces. Or replace them with - or _ – z1ad Jul 24 '16 at 18:26
Yes, that was the problem. Thank you! – Pedro Martins Novaes Jul 24 '16 at 18:40

Daebak · Accepted Answer · 2016-07-24T18:36:00.767

0

rename the input name for example cafe-da-manha-quantidade-0 don't use space or accent character.

<body>
<form method="POST" action="porra.php">
     <div id="refeicao">
            <h1>Segunda</h1>
        Café da manhã
        <br><input name="cafe-da-manha-quantidade-0" type="number" min="0" placeholder="un." />
</form>
<script src="gerar_cardapio_js.js" language="Javascript" type="text/javascript"></script>
</body>

in php use isset for don't produce warnings

if (isset($_POST['cafe-da-manha-quantidade-0'])) {
      $yourvar = $_POST['cafe-da-manha-quantidade-0'];
    }

edited Jul 24 '16 at 18:36

answered Jul 24 '16 at 18:17

Daebak

409
2
9

I am trying to get the value of the first input, not second. I should've delete the part of the code that I'm not using, so I am going to edit the original. – Pedro Martins Novaes Jul 24 '16 at 18:23
It's best to add a helpful explanation why the OP should remove spaces and non-ascii characters for a complete answer – Drakes Jul 24 '16 at 18:31
@Drakes you are right I am new in stackoverflow thanks – Daebak Jul 24 '16 at 18:32
you make in porra.php un echo ($var); :) – Daebak Jul 24 '16 at 18:40
1

Removing all spaces and non-asci characters worked. Thank you. – Pedro Martins Novaes Jul 24 '16 at 18:40

mujuonly · Answer 3 · 2016-07-24T18:27:58.377

<body>
<form method="POST" action="porra.php">
     <div id="refeicao">
            <h1>Segunda</h1>
        Café da manhã
        <br><input name="Cafe da manhã-quantidade-0" type="number" min="0" placeholder="un." />

        <select name="formato" name="Café da manhã-porcionamento-1">
        <option value="" ></option>
        <option value="un" >un</option>
        <option value="g de" >g de</option>
        <option value="ml de" >ml de</option>
        <option value="fatia de" >fatia de</option>
        <option value="fatia média de" >fatia média de</option>
        <option value="fatias de" >fatias de</option>
        <option value="fatias médias de" >fatias médias de</option>
        <option value="C.S de" >C.S de</option>
        <option value="c.c de" >c.c de</option>
        <option value="copo de" >copo de</option>
        <option value="copos de" >copos de</option>
        </select>
        <input type="submit" name="submit"/>
</form>
<script src="gerar_cardapio_js.js" language="Javascript" type="text/javascript"></script>
</body>

I tried this code, changing only the "action" of the form, but it doesn't work. Not only that, but the value should be inputed by the user of the application, not me. — Pedro Martins Novaes, Jul 24 '16 at 18:25
The error indicates the script is porra.php so no change in action is needed — Drakes, Jul 24 '16 at 18:27

Why is this simple php form not posting?

3 Answers3