Sed expression with escape sequence

Question

I need to replace the string '../lib' to '/usr/share/server/bootstrap/lib' in a file bootstrap.sh

I used the following sed expression

sed -i -e 's//././/lib///user//share//server//bootstrap//lib/g' bootstrap.sh

It fails with the log

sed: -e expression #1, char 6: unknown option to `s'

Unable to identity the mistake in the expression.Kindly help.

In addition, you seem to be mixing the meaning of forward slashes and backslashes. — tripleee, Jul 29 '16 at 07:02

score 1 · Accepted Answer · edited May 23 '17 at 12:22

1

You need to escape every . and /

sed -i -e "s/\.\.\/lib/\/usr\/share\/server\/bootstrap\/lib/" bootstrap.sh

Alternative way to avoid two many backslashes using # as delimiter instead of /.

sed -i "s#../libs#/usr/share/server/bootstrap/lib#" bootstrap.sh

edited May 23 '17 at 12:22

Community

answered Jul 29 '16 at 06:59

sozkul

Thanks.. updated it slightly..sed -i -e "s/\.\.\/lib/\/usr\/share\/server\/bootstrap\/lib/g" bootstrap.sh – Priyanka.Patil Jul 29 '16 at 07:21
why not use different delimiter and avoid too many backslashes.. http://stackoverflow.com/documentation/sed/1096/substitution/12280/using-different-delimiters#t=20160729084928666254 – Sundeep Jul 29 '16 at 08:50
Thanks, updated answer. – sozkul Jul 29 '16 at 09:05

1 Answers1