How to get the required string from a QR code scan Result use the ZXING Library

Question

I have a QR code scan result, i would like to get a specific string from the result.

example: if the result is "ROGS,Hudson,J'kobi,Anderson,Harrison,454242,SAM,HARRY, TIM, JOHN,SAMMY,TONNY,SAMON,GROOD,TOD."

And i would like to get the name TONNY from the result string. What is the best way to go about this in Android Java code.

My Current code is as below

public void handleResult(Result rawResult) {
        // Do something with the result here

        Log.e("handler", rawResult.getText()); // Prints scan results
        Log.e("handler", rawResult.getBarcodeFormat().toString()); // Prints the scan format
AlertDialog.Builder builder = new AlertDialog.Builder(this);
        builder.setTitle("Scan Result");
        builder.setMessage(rawResult.getText());
        AlertDialog alert1 = builder.create();
        alert1.show();

        // If you would like to resume scanning, call this method below:
        mScannerView.resumeCameraPreview(this);
}

Is the format of the string always the same as you have shown in the example? — Prerak Sola, Jul 29 '16 at 16:09
Format is same. each name is always separated by a comma, but no of name will keep varying. — Eaby Babu, Jul 29 '16 at 16:29

score 0 · Answer 1 · edited May 23 '17 at 11:58

0

Can't you do a simple string match to check for TONNY or any other name?

String required = "TONNY";
String result = rawResult.getBarcodeFormat().toString();
return result.matches(required)

Edit : to ignore case

result.toLowerCase().contains(required.toLowerCase())

Check this

Edit2 :To get the no., split the result and loop

String array[] = result.split(",")
for(int i=0;i<array.length;i++)
   if(array[i].equals(required))
     return i

edited May 23 '17 at 11:58

Community

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answered Jul 29 '16 at 16:39

sandy

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I will have a number attached with the names so is want that number also, that number will key varying – Eaby Babu Jul 29 '16 at 18:12

How to get the required string from a QR code scan Result use the ZXING Library

1 Answers1