Remove item from a list element?

Question

This may seem odd, but I am trying to remove a part of an item contained in a list. Basically, I am trying to remove a specific character from multiple list elements. For example

list = ['c1','c2','c3','d1','s1']
list.remove('c')

I know that doing that wouldn't work, but is there any way to remove the "c"s in the list, and only the "c"s in Python 3?

What's your expected output? – be_good_do_good Aug 01 '16 at 20:15 — be_good_do_good, Aug 01 '16 at 20:15

score 4 · Accepted Answer · answered Aug 01 '16 at 17:25

4

lst = [s.replace('c','') for s in lst]
# ['1','2','3','d1','s1']

List comprehensions are your friend. Also note the "list" is a keyword in Python, so I highly recommend you do not use it as a variable name.

answered Aug 01 '16 at 17:25

James

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The variable list was an example. This was not meant to be functional Python code. But thank you so much! – Notnert EeBcm Aug 02 '16 at 01:04

Marlon Abeykoon · Answer 2 · 2016-08-01T17:30:09.760

2

Use list comprehensions,

list = ['c1','c2','c3','d1','s1']

list_ = [ x for x in list if "c" not in x ]  # removes elements which has "c"
print list_  # ['d1', 's1']

edited Aug 01 '16 at 17:30

answered Aug 01 '16 at 17:27

Marlon Abeykoon

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Ah. Didn't think of this interpretation of the question, this could very well be what the asker is looking for. +1 – James Aug 01 '16 at 17:29

score 0 · Answer 3 · edited May 23 '17 at 10:28

0

list1 = ['c1','c2','c3','d1','d2']

list2 = []

for i in range (len(list1)):
    if 'c' not in list1[i]:
        list2.append(list1[i])

print (list2) #['d1', 'd2']

and also this link may helpful

Link one

edited May 23 '17 at 10:28

Community

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answered Aug 01 '16 at 17:42

caldera.sac

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Remove item from a list element?

3 Answers3