How to use setImageUri() on Android

Question

Can you help me please? I've tried :

ImageButton imgbt=(ImageButton)findViewById(R.id.imgbutton);
Uri imgUri=Uri.parse("/data/data/MYFOLDER/myimage.png");
imgbt.setImageUri(imgUri);

but I didn't see anything, simply a void button.

Do you need to load the image specifically from a location on disk (like an SD card) or are you fine with loading it as a resource from R? — Charles B, Oct 06 '10 at 08:29

score 18 · Answer 1 · edited Jun 03 '19 at 16:50

18

ImageView.setImageUri only works for local Uri, ie a reference to a local disk file, not a URL to an image on the network.

Here is an example of how to fetch a Bitmap from the network.

    private Bitmap getImageBitmap(String url) {
        Bitmap bm = null;
        try {
            URL aURL = new URL(url);
            URLConnection conn = aURL.openConnection();
            conn.connect();
            InputStream is = conn.getInputStream();
            BufferedInputStream bis = new BufferedInputStream(is);
            bm = BitmapFactory.decodeStream(bis);
            bis.close();
            is.close();
       } catch (IOException e) {
           Log.e(TAG, "Error getting bitmap", e);
       }
       return bm;
    }

Once you have the Bitmap from getImageBitmap(), use: imgView.setImageBitmap(bm);

edited Jun 03 '19 at 16:50

Ribo

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answered Feb 06 '12 at 12:02

SoH

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thanks, this `getImageBitmap` method works for me. Far better than using `setImageURI` – Solostaran14 Nov 06 '12 at 22:07
@iredelweb should really approve this answer. – Max Aug 21 '15 at 12:16
This doesn't answer the question, about how to make .setImageUri to work. It just shows how to read a bitmap from the network. How does that make an image appear in an ImageView ? – Ribo Jun 03 '19 at 16:38

score 8 · Answer 2 · answered Oct 06 '10 at 08:59

8

It should be

Uri imgUri=Uri.parse("file:///data/data/MYFOLDER/myimage.png");

answered Oct 06 '10 at 08:59

bhups

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score 4 · Answer 3 · answered Aug 22 '14 at 22:10

4

How about this one:

Bitmap bitmap = BitmapFactory.decodeFile(fullFileName);
imgProfileImage.setImageBitmap(bitmap);

answered Aug 22 '14 at 22:10

mehrdad seyrafi

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score 2 · Answer 4 · answered Aug 12 '15 at 07:20

2

Its best to avoid building the path by hand, try :

imgbt.setImageUri(Uri.fromFile(new File("/data/data/....")));

answered Aug 12 '15 at 07:20

vine'th

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score 1 · Answer 5 · answered Dec 04 '18 at 07:29

I also met this issue, it did not show anything. I saw something like this in android developer. It didn't use setImageURI.

private Bitmap getBitmapFromUri(Uri uri, Context context) throws IOException {
    ParcelFileDescriptor parcelFileDescriptor =
            context.getContentResolver().openFileDescriptor(uri, "r");
    FileDescriptor fileDescriptor = parcelFileDescriptor.getFileDescriptor();
    Bitmap image = BitmapFactory.decodeFileDescriptor(fileDescriptor);
    parcelFileDescriptor.close();
    return image;
}

Just for your reference.

score 0 · Answer 6 · answered Jan 20 '16 at 07:51

 String imgPath = Environment.getDataDirectory() + "/data/com.wariyum.signage/files/"+ "221215-085656.619.72.jpg";

    //Following lines was expected work, but don't really show up image always - no idea why
    //imgZoom.setImageURI(Uri.parse(imgPath)); 

    //following works always perfectly
            File imgFile = new  File(imgPath);
            if(imgFile.exists()){
                Bitmap myBitmap = BitmapFactory.decodeFile(imgFile.getAbsolutePath());
                imgZoom.setImageBitmap(myBitmap);
            }

Georgiy Chebotarev · Answer 7 · 2018-04-22T18:01:04.023

I solved it with framework. Added this line into the gradle:

implementation 'com.facebook.fresco:fresco:1.8.0'

Init singlton in application-class(or another main class in your app)

Fresco.initialize(applicationContext)

And in finish, use it.

XML:

 <com.facebook.drawee.view.SimpleDraweeView
  android:id="@+id/avatar"
  android:layout_width="110dp"
  android:layout_height="110dp" />

Java:

avatar.setImageURI(user.getAvatarUrl())

How to use setImageUri() on Android

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