I wrote a metaclass that automatically registers its classes in a dict at runtime. In order for it to work properly, it must be able to ignore abstract classes.
The code works really well in Python 2, but I've run into a wall trying to make it compatible with Python 3.
Here's what the code looks like currently:
def AutoRegister(registry, base_type=ABCMeta):
class _metaclass(base_type):
def __init__(self, what, bases=None, attrs=None):
super(_metaclass, self).__init__(what, bases, attrs)
# Do not register abstract classes.
# Note that we do not use `inspect.isabstract` here, as
# that only detects classes with unimplemented abstract
# methods - which is a valid approach, but not what we
# want here.
# :see: http://stackoverflow.com/a/14410942/
metaclass = attrs.get('__metaclass__')
if not (metaclass and issubclass(metaclass, ABCMeta)):
registry.register(self)
return _metaclass
Usage in Python 2 looks like this:
# Abstract classes; these are not registered.
class BaseWidget(object): __metaclass__ = AutoRegister(widget_registry)
class BaseGizmo(BaseWidget): __metaclass__ = ABCMeta
# Concrete classes; these get registered.
class AlphaWidget(BaseWidget): pass
class BravoGizmo(BaseGizmo): pass
What I can't figure out, though, is how to make this work in Python 3.
How can a metaclass determine if it is initializing an abstract class in Python 3?