command line python script run on a file in different directory

Question

I have a script.py in /Users/admin/Desktop and I want to run this script on a file that is in /Users/admin//Desktop/folder/file.txt, without changing the present dir.

Question: what is the most efficient way to do that on command-line ? I am using the following commands and results are not as expected.

$ python script.py --script; /Users/admin/Desktop/file.txt

     raise StopIteration('because of missing file (file.txt)')

 StopIteration: because of missing file (file.txt)

1) The semicolon will prematurely terminate the command. 2) You don't show your code. — mhawke, Aug 04 '16 at 10:42
Possible duplicate of [Temporarily change current working directory in bash to run a command](http://stackoverflow.com/questions/10382141/temporarily-change-current-working-directory-in-bash-to-run-a-command) — Ohad Eytan, Aug 04 '16 at 10:43
Did you consider pass as an argument to the script the path of file.txt? — mandrewcito, Aug 04 '16 at 10:45
@user3698773: post only the code relevant to the problem. See http://stackoverflow.com/help/mcve — mhawke, Aug 04 '16 at 10:53

score 1 · Answer 1 · answered Aug 04 '16 at 10:51

Remove the semicolon because that will prematurely terminate the command.
Pass the correct path to the file to your program. You say it is /Users/admin/Desktop/folder/file.txt, however, your command is using /Users/admin/Desktop/file.txt (it's missing folder)

So the command should (probably) be:

$ python script.py --script /Users/admin/Desktop/folder/file.txt

If that doesn't work you will need to edit your question to show your code.

command line python script run on a file in different directory

1 Answers1