python date format - '2016-08-02T18:43:58Z'

Asked Aug 05 '16 at 13:25

Active Aug 05 '16 at 13:32

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This is a pretty simple request. I'm looking to format the timestamp string - '2016-08-02T18:43:58Z' into a date format that I can compare on with Python.

I made it to here: (datetime.strptime(each_element['sentAt'], "%Y-%m-%d'T'%H:%M:%S'Z'"))

but I'm still getting the error

ValueError: time data '2016-08-02T18:43:58Z' does not match format "%Y-%m-%d'T'%H:%M:%S'Z'"

Pretty sure the error is in the inclusion of the 't' and 'z' but I am stuck as to how to fix. Help?

asked Aug 05 '16 at 13:25

Beth Singley

That timestamp string is an ISO8601-EXT standard format. Surely there's a less hacky way to deal with this in python? Plus one though. (Your specific problem is the single quotation marks around the T and Z literals. Scrap 'em). – Bathsheba Aug 05 '16 at 13:27
Why do you have `'` around `T` and `Z`? – Suever Aug 05 '16 at 13:27
Why did you quote the T, Z? – copper.hat Aug 05 '16 at 13:28

python date format - '2016-08-02T18:43:58Z'

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