Grep/Awk: Find status from table column

Question

dokku ls shows the following but how can I get the status of app-1470418443 using awk for example ?

So that magic command returns running.

-----> App Name           Container Type            Container Id              Status                   
app-1470418443            web                       78a092d176f1              running                  
example                   web                       3b7803c49e04              running                  
example2                  web                       a750f2b4be44              running

Possible duplicate of [grep for contents AFTER pattern](http://stackoverflow.com/questions/10358547/grep-for-contents-after-pattern) — tripleee, Aug 06 '16 at 09:19

score 2 · Answer 1 · answered Aug 05 '16 at 18:12

2

awk '$1=="app-1470418443"{print $NF}'

answered Aug 05 '16 at 18:12

Ed Morton

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James Brown · Answer 2 · 2016-08-07T08:53:14.070

Since there is trailing space in the example output you have to get all non-space characters ([^ ]*) and then all the space (_*, underscore _ represents space as space didn't render at all) in the end of the string ($) and print only the matching parts (grep -o):

$ grep "^app-1470418443 " file | grep -o "[^ ]* *$"
running

Without trailing space, the latter grep would simplify a bit (well 2 bytes) to match only the non-space chars:

$ grep "^app-1470418443 " file | grep -o "[^ ]*$"
running

Grep/Awk: Find status from table column

2 Answers2